2^5=32(x)

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Solution for 2^5=32(x) equation: 



2^5=32(x)

We move all terms to the left:

2^5-(32(x))=0

determiningTheFunctionDomain
-32x+2^5=0

We add all the numbers together, and all the variables

-32x+32=0

We move all terms containing x to the left, all other terms to the right

-32x=-32

x=-32/-32

x=1

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